What is the limit as x approaches infinity of 4^x ?

The limit as x approaches infinity of 4^x is infinity

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limit as x approaches infinity of 4^x

x \to \infty lim (4^{x})

\infty

Solution steps

x \to \infty lim (4^{x})

Apply the common limit:

x \to \infty lim (a^{x}) = \infty, a > 1

= \infty

\int_{- 1}^{2} (7 - 3 x) d x

x (1 + y^{2})^{\frac{1}{2}} d x = y (1 + x^{2})^{\frac{1}{2}} d y

\frac{d y}{d x} + (\frac{3}{x}) y = - x - 5

x \to 0 lim (\frac{sin ( 1 )}{1})

2 \frac{d y}{d x} + \frac{y}{x} = x^{2} y^{- 1}

What is the limit as x approaches infinity of 4^x ?
The limit as x approaches infinity of 4^x is infinity