What is the limit as x approaches 0 of ((2+x)^2+4)/x ?

The limit as x approaches 0 of ((2+x)^2+4)/x is diverges

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

limit as x approaches 0 of ((2+x)^2+4)/x

x \to 0 lim (\frac{( 2 + x ) ^{2} + 4}{x})

diverges

Solution steps

x \to 0 lim (\frac{( 2 + x ) ^{2} + 4}{x})

x \to a - lim f (x) \neq = x \to a + lim f (x)

then the limit does not exist

x \to 0 + lim (\frac{( 2 + x ) ^{2} + 4}{x}) = \infty

x \to 0 - lim (\frac{( 2 + x ) ^{2} + 4}{x}) = - \infty

= diverges

\frac{1}{x ( 5 + ln ( x ) )}

\frac{d y}{d x} = 2 e^{(x - y)}

\frac{d}{d x} (a e^{- x} + b x e^{- x})

x^{2} + 2 x y + 4 y^{2} = 12, (2, 1)

\int (- x^{2} + 6)^{2} - (x^{2} + 4 x)^{2} d x

What is the limit as x approaches 0 of ((2+x)^2+4)/x ?
The limit as x approaches 0 of ((2+x)^2+4)/x is diverges