What is the tangent of f(x)=(x^3-16x)^{14},(4,0) ?

The tangent of f(x)=(x^3-16x)^{14},(4,0) is y=0

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tangent of f(x)=(x^3-16x)^{14},(4,0)

tangent of

f (x) = (x^{3} - 16 x)^{14}, (4, 0)

y = 0

Solution steps

Find the slope of

f (x) = (x^{3} - 16 x)^{14} : \frac{df ( x )}{d x} = 14 (x^{3} - 16 x)^{13} (3 x^{2} - 16)

EN : T i tl e G e n er a l Eq u a t i o n Sl o p e A t P o in t 2 Eq : m = 0

Find the line with slope m=

0

and passing through

(4, 0) : y = 0

y = 0

x \to 8 lim (5)

\int e^{- y} d y

8 x - x^{2}, at x = 1

2 y^{^{'}} + y = 0

\int_{- 1}^{1} t^{2} - 2 d t

What is the tangent of f(x)=(x^3-16x)^{14},(4,0) ?
The tangent of f(x)=(x^3-16x)^{14},(4,0) is y=0