What is the integral from 0 to 0.08 of 120x ?

The integral from 0 to 0.08 of 120x is 0.384

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integral from 0 to 0.08 of 120x

\int_{0}^{0.08} 120 x d x

0.384

Solution steps

\int_{0}^{0.08} 120 x d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 120 \cdot \int_{0}^{0.08} x d x

Apply the Power Rule

: [\frac{x ^{2}}{2}]_{0}^{0.08}

= 120 [\frac{x ^{2}}{2}]_{0}^{0.08}

Simplify

= 120 [0.5 x^{2}]_{0}^{0.08}

Compute the boundaries:

0.0032

= 120 \cdot 0.0032

Simplify

= 0.384

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What is the integral from 0 to 0.08 of 120x ?
The integral from 0 to 0.08 of 120x is 0.384