What is the solution for 11(t+1)(dy)/(dt)-9y=18t ?

The solution for 11(t+1)(dy)/(dt)-9y=18t is y=9t+11+c_{1}(t+1)^{9/11}

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

11(t+1)(dy)/(dt)-9y=18t

11 (t + 1) \frac{d y}{d t} - 9 y = 18 t

y = 9 t + 11 + c_{1} (t + 1)^{\frac{9}{11}}

Solution steps

11 (t + 1) \frac{d y}{d t} - 9 y = 18 t

Solve linear ODE:

y = 9 t + 11 + c_{1} (t + 1)^{\frac{9}{11}}

y = 9 t + 11 + c_{1} (t + 1)^{\frac{9}{11}}

\int_{1}^{e^{2}} x^{4} ln (x) d x

\int 5 x e^{- 3 x} d x

\frac{d y}{d x} = x + 9

x \to 2 - lim (\frac{x}{x ^{2} - 4})

f (x) = \frac{1}{x ^{2} - 9}

What is the solution for 11(t+1)(dy)/(dt)-9y=18t ?
The solution for 11(t+1)(dy)/(dt)-9y=18t is y=9t+11+c_{1}(t+1)^{9/11}