What is the derivative of y=(tan(-1(9x)))2 ?

The derivative of y=(tan(-1(9x)))2 is -18sec^2(9x)

What is the first derivative of y=(tan(-1(9x)))2 ?

The first derivative of y=(tan(-1(9x)))2 is -18sec^2(9x)

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derivative of

y = (tan (- 1 (9 x))) 2

- 18 sec^{2} (9 x)

Solution steps

\frac{d}{d x} (tan (- 1 \cdot 9 x) \cdot 2)

Simplify

tan (- 1 \cdot 9 x) \cdot 2 : - 2 tan (9 x)

= \frac{d}{d x} (- 2 tan (9 x))

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= - 2 \frac{d}{d x} (tan (9 x))

Apply the chain rule:

sec^{2} (9 x) \frac{d}{d x} (9 x)

= sec^{2} (9 x) \frac{d}{d x} (9 x)

\frac{d}{d x} (9 x) = 9

= - 2 sec^{2} (9 x) \cdot 9

Simplify

= - 18 sec^{2} (9 x)

f (x) = (3 t - 1) (2 t - 2)^{- 1}

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\frac{d}{d x} (\frac{2}{2})

\int \frac{e ^{x}}{e ^{2 x} + 3 e ^{x} + 2} d x

\int 5 e^{5 x} d x

What is the derivative of y=(tan(-1(9x)))2 ?
The derivative of y=(tan(-1(9x)))2 is -18sec^2(9x)
What is the first derivative of y=(tan(-1(9x)))2 ?
The first derivative of y=(tan(-1(9x)))2 is -18sec^2(9x)