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Popular >

area x=7y^2,x=4+3y^2

Solution

area

x = 7 y^{2}, x = 4 + 3 y^{2}

Solution

No Solution

Solution steps

Isolate

y

for

x = 7 y^{2} : y = \frac{x}{7}, y = - \frac{x}{7}

Isolate

y

for

x = 4 + 3 y^{2} : y = \frac{x - 4}{3}, y = - \frac{x - 4}{3}

f_{1} (x) = \frac{x}{7}

f_{2} (x) = - \frac{x}{7}

To find the intersection points solve

f_{i} (x) = f_{j} (x)

\frac{x}{7} = - \frac{x}{7} : x = 0

\frac{x}{7} = \frac{x - 4}{3} : x = 7

\frac{x}{7} = - \frac{x - 4}{3} :

No Solution for

x \in R

- \frac{x}{7} = \frac{x - 4}{3} :

No Solution for

x \in R

- \frac{x}{7} = - \frac{x - 4}{3} : x = 7

\frac{x - 4}{3} = - \frac{x - 4}{3} : x = 4

Curves not bounded

= No Solution

Graph

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Frequently Asked Questions (FAQ)

What is area x=7y^2,x=4+3y^2 ?
The answer to area x=7y^2,x=4+3y^2 is No Solution