What is the derivative of f(x)= 4/(1-6x) ?

The derivative of f(x)= 4/(1-6x) is (24)/((1-6x)^2)

What is the first derivative of f(x)= 4/(1-6x) ?

The first derivative of f(x)= 4/(1-6x) is (24)/((1-6x)^2)

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derivative of

f (x) = \frac{4}{1 - 6 x}

\frac{24}{( 1 - 6 x ) ^{2}}

Solution steps

\frac{d}{d x} (\frac{4}{1 - 6 x})

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 4 \frac{d}{d x} (\frac{1}{1 - 6 x})

Apply exponent rule:

\frac{1}{a} = a^{- 1}

= 4 \frac{d}{d x} ((1 - 6 x)^{- 1})

Apply the chain rule:

- \frac{1}{( 1 - 6 x ) ^{2}} \frac{d}{d x} (1 - 6 x)

= - \frac{1}{( 1 - 6 x ) ^{2}} \frac{d}{d x} (1 - 6 x)

\frac{d}{d x} (1 - 6 x) = - 6

= 4 (- \frac{1}{( 1 - 6 x ) ^{2}} (- 6))

Simplify

4 (- \frac{1}{( 1 - 6 x ) ^{2}} (- 6)) : \frac{24}{( 1 - 6 x ) ^{2}}

= \frac{24}{( 1 - 6 x ) ^{2}}

n = 1 \sum \infty \frac{4}{3 ^{n - 1}}

x \to 2 lim (lo g_{10 x} (x))

\frac{\partial}{\partial x} (3 x y^{2} - ln (x))

\frac{2 s}{( s + 1 ) ^{2}}

\frac{x d y}{d x} - y = x^{2} sin (x)

What is the derivative of f(x)= 4/(1-6x) ?
The derivative of f(x)= 4/(1-6x) is (24)/((1-6x)^2)
What is the first derivative of f(x)= 4/(1-6x) ?
The first derivative of f(x)= 4/(1-6x) is (24)/((1-6x)^2)