What is (\partial)/(\partial y)(4y-2x) ?

The answer to (\partial)/(\partial y)(4y-2x) is 4

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(\partial)/(\partial y)(4y-2x)

\frac{\partial}{\partial y} (4 y - 2 x)

4

Solution steps

\frac{\partial}{\partial y} (4 y - 2 x)

Treat

x

as a constant

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{\partial}{\partial y} (4 y) - \frac{\partial}{\partial y} (2 x)

\frac{\partial}{\partial y} (4 y) = 4

\frac{\partial}{\partial y} (2 x) = 0

= 4 - 0

Simplify

= 4

\int 4 - x^{2} x d x

\frac{\partial}{\partial x} (\frac{e ^{y}}{x + y ^{7}})

\frac{d}{d x} (- \frac{4}{( 1 + 2 x ) ^{2}})

\frac{d}{d x} (\frac{3}{4 x})

\int_{0}^{\frac{π}{4}} 8 sec^{2} (x) d x

What is (\partial)/(\partial y)(4y-2x) ?
The answer to (\partial)/(\partial y)(4y-2x) is 4