What is (\partial)/(\partial y)(1+y^2) ?

The answer to (\partial)/(\partial y)(1+y^2) is 2y

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(\partial)/(\partial y)(1+y^2)

\frac{\partial}{\partial y} (1 + y^{2})

2 y

Solution steps

\frac{\partial}{\partial y} (1 + y^{2})

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{\partial}{\partial y} (1) + \frac{\partial}{\partial y} (y^{2})

\frac{\partial}{\partial y} (1) = 0

\frac{\partial}{\partial y} (y^{2}) = 2 y

= 0 + 2 y

Simplify

= 2 y

\frac{d}{d x} (\frac{x ^{2} - 1}{x ^{3}})

\int tan^{11} (x) sec^{8} (x) d x

(2 + x)^{2}

\int_{0}^{1} sec^{3} (x) d x

y^{^{'}} = (x + y + 4)^{2}

What is (\partial)/(\partial y)(1+y^2) ?
The answer to (\partial)/(\partial y)(1+y^2) is 2y