What is the tangent of g(x)=3x^4,(-2,48) ?

The tangent of g(x)=3x^4,(-2,48) is y=-96x-144

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tangent of g(x)=3x^4,(-2,48)

tangent of

g (x) = 3 x^{4}, (- 2, 48)

y = - 96 x - 144

Solution steps

Find the slope of

g (x) = 3 x^{4} : \frac{d g ( x )}{d x} = 12 x^{3}

EN : T i tl e G e n er a l Eq u a t i o n Sl o p e A t P o in t 2 Eq : m = - 96

Find the line with slope m=

- 96

and passing through

(- 2, 48) : y = - 96 x - 144

y = - 96 x - 144

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\frac{d}{d x} (e^{x^{x^{x}}})

\int (- 3 + 4) e^{- x} d x

What is the tangent of g(x)=3x^4,(-2,48) ?
The tangent of g(x)=3x^4,(-2,48) is y=-96x-144