What is the tangent of f(x)= 9/x ,\at x=5 ?

The tangent of f(x)= 9/x ,\at x=5 is y=-9/25 x+18/5

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tangent of f(x)= 9/x ,\at x=5

tangent of

f (x) = \frac{9}{x}, at x = 5

y = - \frac{9}{25} x + \frac{18}{5}

Solution steps

Find the tangent point:

(5, \frac{9}{5})

Find the slope of

f (x) = \frac{9}{x} : \frac{df ( x )}{d x} = - \frac{9}{x ^{2}}

EN : T i tl e G e n er a l Eq u a t i o n Sl o p e A t P o in t 2 Eq : m = - \frac{9}{25}

Find the line with slope m=

- \frac{9}{25}

and passing through

(5, \frac{9}{5}) : y = - \frac{9}{25} x + \frac{18}{5}

y = - \frac{9}{25} x + \frac{18}{5}

\frac{d}{d x} (\frac{2 x - 3}{x ^{2}})

n = 0 \sum \infty i^{n}

(x + \frac{1}{x})^{4}

\frac{d}{d x} (\frac{sec ( x )}{3 + sec ( x )})

\frac{\partial}{\partial z} (x^{2} e^{y z^{2}})

What is the tangent of f(x)= 9/x ,\at x=5 ?
The tangent of f(x)= 9/x ,\at x=5 is y=-9/25 x+18/5