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Popular >

y^{''}+25y=0

Solution

y^{^{''}} + 25 y = 0

Solution

y = c_{1} cos (5 t) + c_{2} sin (5 t)

Solution steps

y^{''} (t) + 25 y = 0

Solve linear ODE:

y = c_{1} cos (5 t) + c_{2} sin (5 t)

y = c_{1} cos (5 t) + c_{2} sin (5 t)

Popular Examples

derivative of sqrt(x)sec(1/(sqrt(x)))

\frac{d}{d x} (x sec (\frac{1}{x}))

integral of (x^3)/(sqrt(4x^2+16))

\int \frac{x ^{3}}{4 x ^{2} + 16} d x

integral of (e^{-3x})/(1-e^{-3x)}

\int \frac{e ^{- 3 x}}{1 - e ^{- 3 x}} d x

inverse oflaplace 9 inverse laplace

9

limit as x approaches infinity of 3/0

x \to \infty lim (\frac{3}{0})

Frequently Asked Questions (FAQ)

What is the solution for y^{''}+25y=0 ?
The solution for y^{''}+25y=0 is y=c_{1}cos(5t)+c_{2}sin(5t)