What is laplacetransform cos(θ) ?

The answer to laplacetransform cos(θ) is s/(s^2+1)

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laplacetransform cos(θ)

laplace transform

cos (θ)

\frac{s}{s ^{2} + 1}

Solution steps

L {cos (θ)}

Use Laplace Transform table:

L {cos (a t)} = \frac{s}{s ^{2} + a ^{2}}

L {cos (θ)} = \frac{s}{s ^{2} + 1 ^{2}}

= \frac{s}{s ^{2} + 1 ^{2}}

= \frac{s}{s ^{2} + 1}

x \to 0 lim (e^{x})

y = \frac{1}{x ^{2} + 1}

\int - \frac{2}{9 - 9 x ^{2}} d x

\int \frac{1}{( x ^{2} + 2 x + 5 ) ^{3}} d x

sec (tan (x))

What is laplacetransform cos(θ) ?
The answer to laplacetransform cos(θ) is s/(s^2+1)