What is the limit as x approaches 25 of log_{5}(x) ?

The limit as x approaches 25 of log_{5}(x) is 2

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limit as x approaches 25 of log_{5}(x)

x \to 25 lim (lo g_{5} (x))

2

Solution steps

x \to 25 lim (lo g_{5} (x))

Plug in the value

x = 25

= lo g_{5} (25)

Simplify

lo g_{5} (25) : 2

= 2

\frac{d}{d x} (x^{5} ln (2 x))

f (x) = (\frac{x ^{2}}{x - 1})^{2}

\int_{0}^{1} 1 d x

\int e^{- 4}

f (x) = - x^{3} + 4 x^{2} - 1, at x = 1

What is the limit as x approaches 25 of log_{5}(x) ?
The limit as x approaches 25 of log_{5}(x) is 2