What is the derivative of 0.01x^3-0.45x^2+2.43x+300 ?

The derivative of 0.01x^3-0.45x^2+2.43x+300 is 0.03x^2-0.9x+2.43

What is the first derivative of 0.01x^3-0.45x^2+2.43x+300 ?

The first derivative of 0.01x^3-0.45x^2+2.43x+300 is 0.03x^2-0.9x+2.43

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\frac{d}{d x} (0.01 x^{3} - 0.45 x^{2} + 2.43 x + 300)

0.03 x^{2} - 0.9 x + 2.43

Solution steps

\frac{d}{d x} (0.01 x^{3} - 0.45 x^{2} + 2.43 x + 300)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (0.01 x^{3}) - \frac{d}{d x} (0.45 x^{2}) + \frac{d}{d x} (2.43 x) + \frac{d}{d x} (300)

\frac{d}{d x} (0.01 x^{3}) = 0.03 x^{2}

\frac{d}{d x} (0.45 x^{2}) = 0.9 x

\frac{d}{d x} (2.43 x) = 2.43

\frac{d}{d x} (300) = 0

= 0.03 x^{2} - 0.9 x + 2.43 + 0

Simplify

= 0.03 x^{2} - 0.9 x + 2.43

\int_{1}^{2} \frac{2}{x} d x

\int \frac{- 2}{x} d x

\frac{15 + 5 5}{12} a^{3}

(1 + x^{2}) y^{^{''}} = 2 x (y^{^{'}})^{2}

y^{^{'}} + \frac{1.93}{293 + t} \cdot y = 2.7249

What is the derivative of 0.01x^3-0.45x^2+2.43x+300 ?
The derivative of 0.01x^3-0.45x^2+2.43x+300 is 0.03x^2-0.9x+2.43
What is the first derivative of 0.01x^3-0.45x^2+2.43x+300 ?
The first derivative of 0.01x^3-0.45x^2+2.43x+300 is 0.03x^2-0.9x+2.43