What is the limit as x approaches infinity of e^{-x}-ln(x) ?

The limit as x approaches infinity of e^{-x}-ln(x) is -infinity

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

limit as x approaches infinity of e^{-x}-ln(x)

x \to \infty lim (e^{- x} - ln (x))

- \infty

Solution steps

x \to \infty lim (e^{- x} - ln (x))

x \to a lim [f (x) \pm g (x)] = x \to a lim f (x) \pm x \to a lim g (x)

With the exception of indeterminate form

= x \to \infty lim (e^{- x}) - x \to \infty lim (ln (x))

x \to \infty lim (e^{- x}) = 0

x \to \infty lim (ln (x)) = \infty

= 0 - \infty

Apply Infinity Property:

c - \infty = - \infty

= - \infty

\int \frac{8 x ^{2} + x + 73}{( x + 1 ) ( x ^{2} + 9 )} d x

7 (x^{3} - x)^{4}

\frac{d}{d x} (\frac{3 x - 8}{x ^{2} - 1})

y^{^{'}} + \frac{3 y}{x} = \frac{3}{x}

y = \frac{9}{x ^{- 6}}

What is the limit as x approaches infinity of e^{-x}-ln(x) ?
The limit as x approaches infinity of e^{-x}-ln(x) is -infinity