What is the tangent of 5x^2+xy+5y^2=11,(1,1) ?

The tangent of 5x^2+xy+5y^2=11,(1,1) is y=-x+2

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tangent of 5x^2+xy+5y^2=11,(1,1)

tangent of

5 x^{2} + x y + 5 y^{2} = 11, (1, 1)

y = - x + 2

Solution steps

Find the slope of

5 x^{2} + x y + 5 y^{2} = 11 : \frac{d y}{d x} = \frac{- 10 x - y}{x + 10 y}

EN : T i tl e G e n er a l Eq u a t i o n Sl o p e A t P o in t 2 Eq : m = - 1

Find the line with slope m=

- 1

and passing through

(1, 1) : y = - x + 2

y = - x + 2

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\frac{d}{d x} (sin^{5} (x^{2} + 1)^{7})

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\frac{\partial}{\partial x} (cos (x) - x cos (y) - y)

What is the tangent of 5x^2+xy+5y^2=11,(1,1) ?
The tangent of 5x^2+xy+5y^2=11,(1,1) is y=-x+2