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Popular >

y^'=e^{x-2y}

Solution

y^{^{'}} = e^{x - 2 y}

Solution

y = \frac{ln ( 2 e ^{x} + c _{1} )}{2}

Solution steps

y^{'} (x) = e^{x - 2 y}

Solve separable ODE:

y = \frac{ln ( 2 e ^{x} + c _{1} )}{2}

y = \frac{ln ( 2 e ^{x} + c _{1} )}{2}

Graph

Popular Examples

area x=-2,x=3,y=2x^2+6,y=0 area

x = - 2, x = 3, y = 2 x^{2} + 6, y = 0

limit as x approaches 0+of (x^2+1)/x

x \to 0 + lim (\frac{x ^{2} + 1}{x})

limit as x approaches 2 of 1/(x^2-9)

x \to 2 lim (\frac{1}{x ^{2} - 9})

y^{^{''}} + 15 y = 0

derivative of {f}(x(x)^{{g}(x)})

\frac{d}{d x} (f (x) (x)^{g (x)})

Frequently Asked Questions (FAQ)

What is the solution for y^'=e^{x-2y} ?
The solution for y^'=e^{x-2y} is y=(ln(2e^x+c_{1}))/2