What is the limit as z approaches-2 of (z^2-9)/(z-3) ?

The limit as z approaches-2 of (z^2-9)/(z-3) is 1

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limit as z approaches-2 of (z^2-9)/(z-3)

z \to - 2 lim (\frac{z ^{2} - 9}{z - 3})

1

Solution steps

z \to - 2 lim (\frac{z ^{2} - 9}{z - 3})

Plug in the value

z = - 2

= \frac{( - 2 ) ^{2} - 9}{- 2 - 3}

Simplify

\frac{( - 2 ) ^{2} - 9}{- 2 - 3} : 1

= 1

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What is the limit as z approaches-2 of (z^2-9)/(z-3) ?
The limit as z approaches-2 of (z^2-9)/(z-3) is 1