What is the tangent of f(x)=x^2+4,\at x=3 ?

The tangent of f(x)=x^2+4,\at x=3 is y=6x-5

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tangent of f(x)=x^2+4,\at x=3

tangent of

f (x) = x^{2} + 4, at x = 3

y = 6 x - 5

Solution steps

Find the tangent point:

(3, 13)

Find the slope of

f (x) = x^{2} + 4 : \frac{df ( x )}{d x} = 2 x

EN : T i tl e G e n er a l Eq u a t i o n Sl o p e A t P o in t 2 Eq : m = 6

Find the line with slope m=

6

and passing through

(3, 13) : y = 6 x - 5

y = 6 x - 5

\int x (2 x + 3)^{99} d x

x^{2} - 7 x

\int_{0}^{8} x 1 + x d x

\frac{1}{6 x - 1}

\int - \frac{6}{π} x d x

What is the tangent of f(x)=x^2+4,\at x=3 ?
The tangent of f(x)=x^2+4,\at x=3 is y=6x-5