What is the derivative of y=(-13)/(\sqrt[4]{x)} ?

The derivative of y=(-13)/(\sqrt[4]{x)} is (13)/(4x^{5/4)}

What is the first derivative of y=(-13)/(\sqrt[4]{x)} ?

The first derivative of y=(-13)/(\sqrt[4]{x)} is (13)/(4x^{5/4)}

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derivative of

y = \frac{- 13}{4 x}

\frac{13}{4 x ^{\frac{5}{4}}}

Solution steps

\frac{d}{d x} (\frac{- 13}{4 x})

Simplify

\frac{- 13}{4 x} : - \frac{13}{4 x}

= \frac{d}{d x} (- \frac{13}{4 x})

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= - 13 \frac{d}{d x} (\frac{1}{4 x})

Apply exponent rule:

\frac{1}{a} = a^{- 1}

= - 13 \frac{d}{d x} (x^{- \frac{1}{4}})

Apply the Power Rule:

\frac{d}{d x} (x^{a}) = a \cdot x^{a - 1}

= - 13 (- \frac{1}{4} x^{- \frac{1}{4} - 1})

Simplify

- 13 (- \frac{1}{4} x^{- \frac{1}{4} - 1}) : \frac{13}{4 x ^{\frac{5}{4}}}

= \frac{13}{4 x ^{\frac{5}{4}}}

g (x) = x^{2} (1 - 3 x)

\int b x \cdot sin (\frac{π x}{2 a}) d x

\frac{\partial}{\partial y} (5 x^{2} - 2 x y + 3 y^{3})

(5.8) (3.9)

y^{^{''}} - y = \frac{1}{e ^{x} + e ^{- x}}

What is the derivative of y=(-13)/(\sqrt[4]{x)} ?
The derivative of y=(-13)/(\sqrt[4]{x)} is (13)/(4x^{5/4)}
What is the first derivative of y=(-13)/(\sqrt[4]{x)} ?
The first derivative of y=(-13)/(\sqrt[4]{x)} is (13)/(4x^{5/4)}