What is the solution for (dy)/(dt)=2ty^2+3y^2 ?

The solution for (dy)/(dt)=2ty^2+3y^2 is y=-1/(t^2+3t+c_{1)}

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(dy)/(dt)=2ty^2+3y^2

\frac{d y}{d t} = 2 t y^{2} + 3 y^{2}

y = - \frac{1}{t ^{2} + 3 t + c _{1}}

Solution steps

\frac{d y}{d t} = 2 t y^{2} + 3 y^{2}

Solve separable ODE:

y = - \frac{1}{t ^{2} + 3 t + c _{1}}

y = - \frac{1}{t ^{2} + 3 t + c _{1}}

x \to + 0 + lim ((7 x)^{x})

\int_{- \infty}^{\infty} x e^{x^{2}} d x

\frac{d y}{d x} = - k (y - a)

3 y ln (x) - x y^{^{'}} = 0

\frac{d}{d x} (tan (x^{2} - 4 x^{5}))

What is the solution for (dy)/(dt)=2ty^2+3y^2 ?
The solution for (dy)/(dt)=2ty^2+3y^2 is y=-1/(t^2+3t+c_{1)}