What is the derivative of f(x)=(x-7)(5x+1) ?

The derivative of f(x)=(x-7)(5x+1) is 10x-34

What is the first derivative of f(x)=(x-7)(5x+1) ?

The first derivative of f(x)=(x-7)(5x+1) is 10x-34

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derivative of

f (x) = (x - 7) (5 x + 1)

10 x - 34

Solution steps

\frac{d}{d x} ((x - 7) (5 x + 1))

Apply the Product Rule:

(f \cdot g)^{'} = f^{'} \cdot g + f \cdot g^{'}

f = x - 7, g = 5 x + 1

= \frac{d}{d x} (x - 7) (5 x + 1) + \frac{d}{d x} (5 x + 1) (x - 7)

\frac{d}{d x} (x - 7) = 1

\frac{d}{d x} (5 x + 1) = 5

= 1 \cdot (5 x + 1) + 5 (x - 7)

Simplify

1 \cdot (5 x + 1) + 5 (x - 7) : 10 x - 34

= 10 x - 34

e^{\frac{1}{t}}

\int \frac{x}{x + 6} d x

\frac{d}{d x} (e^{x} + 2^{(- x)} + 2 cos (x) - 6)

\frac{d y}{d x} + 8 y = e^{x} y^{- 6}

\frac{2 x d y}{d x} + y = 6 x

What is the derivative of f(x)=(x-7)(5x+1) ?
The derivative of f(x)=(x-7)(5x+1) is 10x-34
What is the first derivative of f(x)=(x-7)(5x+1) ?
The first derivative of f(x)=(x-7)(5x+1) is 10x-34