What is the derivative of-(cos(2x)/2) ?

The derivative of-(cos(2x)/2) is sin(2x)

What is the first derivative of-(cos(2x)/2) ?

The first derivative of-(cos(2x)/2) is sin(2x)

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\frac{d}{d x} (- \frac{cos ( 2 x )}{2})

sin (2 x)

Solution steps

\frac{d}{d x} (- \frac{cos ( 2 x )}{2})

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= - \frac{1}{2} \frac{d}{d x} (cos (2 x))

Apply the chain rule:

- sin (2 x) \frac{d}{d x} (2 x)

= - sin (2 x) \frac{d}{d x} (2 x)

\frac{d}{d x} (2 x) = 2

= - \frac{1}{2} (- sin (2 x) \cdot 2)

Simplify

- \frac{1}{2} (- sin (2 x) \cdot 2) : sin (2 x)

= sin (2 x)

\int t^{5} ln (t) d t

e^{(e^{(x)} - x)}

f (x) = tan (4 x^{2} - 3 x - 4)

f (x) = 2 x^{2} + 3 x, (- 3, 9)

\frac{d}{d x} ((x^{3} - 1)^{4})

What is the derivative of-(cos(2x)/2) ?
The derivative of-(cos(2x)/2) is sin(2x)
What is the first derivative of-(cos(2x)/2) ?
The first derivative of-(cos(2x)/2) is sin(2x)