What is the derivative of 9/(x+2) ?

The derivative of 9/(x+2) is -9/((x+2)^2)

What is the first derivative of 9/(x+2) ?

The first derivative of 9/(x+2) is -9/((x+2)^2)

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derivative of

\frac{9}{x + 2}

- \frac{9}{( x + 2 ) ^{2}}

Solution steps

\frac{d}{d x} (\frac{9}{x + 2})

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 9 \frac{d}{d x} (\frac{1}{x + 2})

Apply exponent rule:

\frac{1}{a} = a^{- 1}

= 9 \frac{d}{d x} ((x + 2)^{- 1})

Apply the chain rule:

- \frac{1}{( x + 2 ) ^{2}} \frac{d}{d x} (x + 2)

= - \frac{1}{( x + 2 ) ^{2}} \frac{d}{d x} (x + 2)

\frac{d}{d x} (x + 2) = 1

= 9 (- \frac{1}{( x + 2 ) ^{2}} \cdot 1)

Simplify

9 (- \frac{1}{( x + 2 ) ^{2}} \cdot 1) : - \frac{9}{( x + 2 ) ^{2}}

= - \frac{9}{( x + 2 ) ^{2}}

\int 3 x^{2} + 10 x - 5 d x

x \to - 2 - lim (- 3 x^{2} - 5 x + 3)

\int 10 csc^{2} (x) - sin (x) d x

5 sin (t) cos (t)

cos (x), sin (2 x), x = 0, x = \frac{π}{2}

What is the derivative of 9/(x+2) ?
The derivative of 9/(x+2) is -9/((x+2)^2)
What is the first derivative of 9/(x+2) ?
The first derivative of 9/(x+2) is -9/((x+2)^2)