What is the tangent of f(x)=x^4+4e^x,(0,4) ?

The tangent of f(x)=x^4+4e^x,(0,4) is y=4x+4

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tangent of f(x)=x^4+4e^x,(0,4)

tangent of

f (x) = x^{4} + 4 e^{x}, (0, 4)

y = 4 x + 4

Solution steps

Find the slope of

f (x) = x^{4} + 4 e^{x} : \frac{df ( x )}{d x} = 4 x^{3} + 4 e^{x}

Compute the slope of

f (x) = x^{4} + 4 e^{x}

(0, 4) : m = 4

Find the line with slope m=

4

and passing through

(0, 4) : y = 4 x + 4

y = 4 x + 4

\frac{d y}{d t} = - 2 (y - 4)

\int \frac{x ^{2} + 16}{x ^{4}} d x

x \to 1 lim (x^{2} + 3 x - 4)

\frac{( x ^{2} e ^{x} )}{x ^{2} + e ^{x}}

\frac{d}{d x} (5 e^{x} (cos (x) - sin (x)))

What is the tangent of f(x)=x^4+4e^x,(0,4) ?
The tangent of f(x)=x^4+4e^x,(0,4) is y=4x+4