What is the derivative of 3cos(x^2-1) ?

The derivative of 3cos(x^2-1) is -6xsin(x^2-1)

What is the first derivative of 3cos(x^2-1) ?

The first derivative of 3cos(x^2-1) is -6xsin(x^2-1)

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\frac{d}{d x} (3 cos (x^{2} - 1))

- 6 x sin (x^{2} - 1)

Solution steps

\frac{d}{d x} (3 cos (x^{2} - 1))

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 3 \frac{d}{d x} (cos (x^{2} - 1))

Apply the chain rule:

- sin (x^{2} - 1) \frac{d}{d x} (x^{2} - 1)

= - sin (x^{2} - 1) \frac{d}{d x} (x^{2} - 1)

\frac{d}{d x} (x^{2} - 1) = 2 x

= 3 (- sin (x^{2} - 1) \cdot 2 x)

Simplify

= - 6 x sin (x^{2} - 1)

\int_{5}^{7} \frac{1}{4 + ( x - 5 ) ^{2}} d x

x \to 2 lim (x (x + 4))

\frac{x ^{2}}{x - 7}

\int \frac{1}{x - 3} d x

What is the derivative of 3cos(x^2-1) ?
The derivative of 3cos(x^2-1) is -6xsin(x^2-1)
What is the first derivative of 3cos(x^2-1) ?
The first derivative of 3cos(x^2-1) is -6xsin(x^2-1)