What is the integral from 0 to 1 of 4/(x^2) ?

The integral from 0 to 1 of 4/(x^2) is diverges

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integral from 0 to 1 of 4/(x^2)

\int_{0}^{1} \frac{4}{x ^{2}} d x

diverges

Solution steps

\int_{0}^{1} \frac{4}{x ^{2}} d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 4 \cdot \int_{0}^{1} \frac{1}{x ^{2}} d x

Apply the Power Rule

: [- \frac{1}{x}]_{0}^{1}

= 4 [- \frac{1}{x}]_{0}^{1}

Compute the boundaries:

diverges

= diverges

x \to 0 + lim (x^{- \frac{4}{l n ( x )}})

x \to 0 - lim (\frac{- 1}{x})

y = lo g_{5} (5 x + 4)

\frac{\partial}{\partial y} (4 - x^{2} - 4 y^{2})

n = 0 \sum \infty 1 0^{n} x^{n}

What is the integral from 0 to 1 of 4/(x^2) ?
The integral from 0 to 1 of 4/(x^2) is diverges