What is the integral of (2x+1)e^{x(x+1)} ?

The integral of (2x+1)e^{x(x+1)} is e^{x(x+1)}+C

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integral of (2x+1)e^{x(x+1)}

\int (2 x + 1) e^{x (x + 1)} d x

e^{x (x + 1)} + C

Solution steps

\int (2 x + 1) e^{x (x + 1)} d x

Apply u-substitution

: \int e^{u} d u

= \int e^{u} d u

Use the common integral:

\int e^{u} d u = e^{u}

= e^{u}

Substitute back

u = x (x + 1)

= e^{x (x + 1)}

Add a constant to the solution

= e^{x (x + 1)} + C

x \to 3 lim (2 x^{2} - 5 x + 3)

(10 x^{2} - 20 x + 20) e^{x}

y = 4 e^{2 x}

\int_{0}^{4} 0.125 x d x

n = 1 \sum \infty 6 e^{- 2 n}

What is the integral of (2x+1)e^{x(x+1)} ?
The integral of (2x+1)e^{x(x+1)} is e^{x(x+1)}+C