What is the derivative of x^3-3x^2+1 ?

The derivative of x^3-3x^2+1 is 3x^2-6x

What is the first derivative of x^3-3x^2+1 ?

The first derivative of x^3-3x^2+1 is 3x^2-6x

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\frac{d}{d x} (x^{3} - 3 x^{2} + 1)

3 x^{2} - 6 x

Solution steps

\frac{d}{d x} (x^{3} - 3 x^{2} + 1)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (x^{3}) - \frac{d}{d x} (3 x^{2}) + \frac{d}{d x} (1)

\frac{d}{d x} (x^{3}) = 3 x^{2}

\frac{d}{d x} (3 x^{2}) = 6 x

\frac{d}{d x} (1) = 0

= 3 x^{2} - 6 x + 0

Simplify

= 3 x^{2} - 6 x

\frac{d}{d x} (ln (1 + x^{2}))

\int \frac{1}{10 x ^{6}} d x

f (x) = x x + 1

(y - sin^{2} (x)) d x + sin (x) d y = 0

y^{^{'}} e^{- 12 x} + 12 e^{- 12 x} y = - 6 e^{- 8 x}

What is the derivative of x^3-3x^2+1 ?
The derivative of x^3-3x^2+1 is 3x^2-6x
What is the first derivative of x^3-3x^2+1 ?
The first derivative of x^3-3x^2+1 is 3x^2-6x