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Popular >

xy^'+y=9xy^2,y(1)=2

Solution

x y^{^{'}} + y = 9 x y^{2}, y (1) = 2

Solution

y = \frac{2}{x ( - 18 ln ( x ) + 1 )}

Solution steps

x y^{'} (x) + y = 9 x y^{2}

Solve Bernoulli ODE:

y = \frac{2}{x ( - 18 ln ( x ) + 1 )}

y = \frac{2}{x ( - 18 ln ( x ) + 1 )}

Graph

Popular Examples

area x^3-6x,-2x area

x^{3} - 6 x, - 2 x

area x^2-6x,-x^2+6 area

x^{2} - 6 x, - x^{2} + 6

derivative of f(x)=2x^2-4x+3 derivative of

f (x) = 2 x^{2} - 4 x + 3

y^{''}+y^'+y=1+t+t^2

y^{^{''}} + y^{^{'}} + y = 1 + t + t^{2}

x(dy)/(dx)=(2y)

x \frac{d y}{d x} = (2 y)

Frequently Asked Questions (FAQ)

What is the solution for xy^'+y=9xy^2,y(1)=2 ?
The solution for xy^'+y=9xy^2,y(1)=2 is y= 2/(x(-18ln(x)+1))