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Popular >

y^'=(-(xy+1))/(xy+1)

Solution

y^{^{'}} = \frac{- ( x y + 1 )}{x y + 1}

Solution

y = - x + c_{1}

Solution steps

y^{'} (x) = \frac{- ( x y + 1 )}{x y + 1}

Simplify

y^{^{'}} (x) = - 1

If

f^{^{'}} (x) = g (x)

then

f (x) = \int g (x) d x

y = \int - 1 d x

\int - 1 d x = - x + c_{1}

y = - x + c_{1}

Graph

Popular Examples

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(2y+2t-7)dt+(4y+2t-1)dy=0,y(-1)=2

(2 y + 2 t - 7) d t + (4 y + 2 t - 1) d y = 0, y (- 1) = 2

Frequently Asked Questions (FAQ)

What is the solution for y^'=(-(xy+1))/(xy+1) ?
The solution for y^'=(-(xy+1))/(xy+1) is y=-x+c_{1}