What is the derivative of (x^2+1)^5 ?

The derivative of (x^2+1)^5 is 10x(x^2+1)^4

What is the first derivative of (x^2+1)^5 ?

The first derivative of (x^2+1)^5 is 10x(x^2+1)^4

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derivative of

(x^{2} + 1)^{5}

10 x (x^{2} + 1)^{4}

Solution steps

\frac{d}{d x} ((x^{2} + 1)^{5})

Apply the chain rule:

5 (x^{2} + 1)^{4} \frac{d}{d x} (x^{2} + 1)

= 5 (x^{2} + 1)^{4} \frac{d}{d x} (x^{2} + 1)

\frac{d}{d x} (x^{2} + 1) = 2 x

= 5 (x^{2} + 1)^{4} \cdot 2 x

Simplify

= 10 x (x^{2} + 1)^{4}

\frac{d}{d x} (tan (e^{s i n (x)}))

\int t \cdot e^{4 t} d t

f (x) = \frac{1 + x + x ^{2}}{1 - x ^{2}}

f (x) = \frac{4 x + 5}{4 x - 5}

\frac{d}{d x} (ln (sin (x)) + cos^{2} (x))

What is the derivative of (x^2+1)^5 ?
The derivative of (x^2+1)^5 is 10x(x^2+1)^4
What is the first derivative of (x^2+1)^5 ?
The first derivative of (x^2+1)^5 is 10x(x^2+1)^4