What is the solution for (dy}{dx}=\frac{3y)/x ,x>0 ?

The solution for (dy}{dx}=\frac{3y)/x ,x>0 is y=c_{1}x^3

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(dy}{dx}=\frac{3y)/x ,x>0

\frac{d y}{d x} = \frac{3 y}{x}, x > 0

y = c_{1} x^{3}

Solution steps

\frac{d y}{d x} = \frac{3 y}{x}

Solve separable ODE:

y = c_{1} x^{3}

y = c_{1} x^{3}

\int \frac{3}{x ln ( x )} d x

\frac{d}{d x} (\frac{x ^{3}}{39} + \frac{13}{4 x})

f (x) = \frac{2}{t ^{3}}

\frac{d ^{2} y}{d x ^{2}}, x^{2} + y^{2} = 16

\frac{\partial}{\partial z} (x y + yz - x z)

What is the solution for (dy}{dx}=\frac{3y)/x ,x>0 ?
The solution for (dy}{dx}=\frac{3y)/x ,x>0 is y=c_{1}x^3