What is the derivative of h(x)=tan(4x^2-3x-4) ?

The derivative of h(x)=tan(4x^2-3x-4) is sec^2(4x^2-3x-4)(8x-3)

What is the first derivative of h(x)=tan(4x^2-3x-4) ?

The first derivative of h(x)=tan(4x^2-3x-4) is sec^2(4x^2-3x-4)(8x-3)

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derivative of

h (x) = tan (4 x^{2} - 3 x - 4)

sec^{2} (4 x^{2} - 3 x - 4) (8 x - 3)

Solution steps

\frac{d}{d x} (tan (4 x^{2} - 3 x - 4))

Apply the chain rule:

sec^{2} (4 x^{2} - 3 x - 4) \frac{d}{d x} (4 x^{2} - 3 x - 4)

= sec^{2} (4 x^{2} - 3 x - 4) \frac{d}{d x} (4 x^{2} - 3 x - 4)

\frac{d}{d x} (4 x^{2} - 3 x - 4) = 8 x - 3

= sec^{2} (4 x^{2} - 3 x - 4) (8 x - 3)

\int 7 cot^{4} (x) d x

2 x y - 9 x^{2} + (2 y + x^{2} + 1) y^{^{'}} = 0

\frac{d}{d x} (5 tan (2 x^{3}) + \frac{2}{x ^{2}})

y^{^{'}} = - (1 + y)^{4}, y (1) = 2

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What is the derivative of h(x)=tan(4x^2-3x-4) ?
The derivative of h(x)=tan(4x^2-3x-4) is sec^2(4x^2-3x-4)(8x-3)
What is the first derivative of h(x)=tan(4x^2-3x-4) ?
The first derivative of h(x)=tan(4x^2-3x-4) is sec^2(4x^2-3x-4)(8x-3)