What is (\partial)/(\partial x)(2y+2x^2) ?

The answer to (\partial)/(\partial x)(2y+2x^2) is 4x

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(\partial)/(\partial x)(2y+2x^2)

\frac{\partial}{\partial x} (2 y + 2 x^{2})

4 x

Solution steps

\frac{\partial}{\partial x} (2 y + 2 x^{2})

Treat

y

as a constant

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{\partial}{\partial x} (2 y) + \frac{\partial}{\partial x} (2 x^{2})

\frac{\partial}{\partial x} (2 y) = 0

\frac{\partial}{\partial x} (2 x^{2}) = 4 x

= 0 + 4 x

Simplify

= 4 x

3 x^{2} y^{^{'}} + x^{3} y^{^{''}} = x

\int \frac{x ^{2} - 3}{- x ^{3} + 9 x + 1} d x

\int (2 x - 3) (5 x + 1) d x

\int_{1}^{5} \frac{4}{x} d x

n = 1 \sum \infty \frac{2}{3 ^{n} + 1}

What is (\partial)/(\partial x)(2y+2x^2) ?
The answer to (\partial)/(\partial x)(2y+2x^2) is 4x