What is the solution for y^'=(1-2x)y^2,y(0)=-1/30 ?

The solution for y^'=(1-2x)y^2,y(0)=-1/30 is y=-1/(x-x^2+30)

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y^'=(1-2x)y^2,y(0)=-1/30

y^{^{'}} = (1 - 2 x) y^{2}, y (0) = - \frac{1}{30}

y = - \frac{1}{x - x ^{2} + 30}

Solution steps

y^{'} (x) = (1 - 2 x) y^{2}

Solve separable ODE:

y = - \frac{1}{x - x ^{2} + 30}

y = - \frac{1}{x - x ^{2} + 30}

\int_{0}^{8} k (8 - x)

f (x) = - 6 x^{2} + 7 x

f (x) = - 1 - 4 e^{- \frac{x}{3}}, at x = 8

x y^{^{'}} - y = 2 x^{2} - x - 1

\int sin^{2} (\frac{π x}{l}) d x

What is the solution for y^'=(1-2x)y^2,y(0)=-1/30 ?
The solution for y^'=(1-2x)y^2,y(0)=-1/30 is y=-1/(x-x^2+30)