What is the derivative of f(4k)=x^2-2x ?

The derivative of f(4k)=x^2-2x is 2x-2

What is the first derivative of f(4k)=x^2-2x ?

The first derivative of f(4k)=x^2-2x is 2x-2

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

derivative of

f (4 k) = x^{2} - 2 x

2 x - 2

Solution steps

\frac{d}{d x} (x^{2} - 2 x)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (x^{2}) - \frac{d}{d x} (2 x)

\frac{d}{d x} (x^{2}) = 2 x

\frac{d}{d x} (2 x) = 2

= 2 x - 2

\int \frac{17 - 17 x}{1 - x} d x

\frac{d}{d x} (ln (x^{2} + y^{2} + z^{2}))

\frac{d}{d x} (lo g_{10} (x^{2} + y))

\frac{\partial}{\partial x} (- 2 e^{- x^{2} - y^{2}} x cos (x y) - e^{- x^{2} - y^{2}} y sin (x y))

\frac{\partial}{\partial x} (\frac{1}{x y} (x^{2} y^{2} + y + x))

What is the derivative of f(4k)=x^2-2x ?
The derivative of f(4k)=x^2-2x is 2x-2
What is the first derivative of f(4k)=x^2-2x ?
The first derivative of f(4k)=x^2-2x is 2x-2