What is the integral of (x^5)/(1+x^{12)} ?

The integral of (x^5)/(1+x^{12)} is 1/6 arctan(x^6)+C

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integral of (x^5)/(1+x^{12)}

\int \frac{x ^{5}}{1 + x ^{12}} d x

\frac{1}{6} arctan (x^{6}) + C

Solution steps

\int \frac{x ^{5}}{1 + x ^{12}} d x

Apply u-substitution

: \int \frac{1}{6 ( 1 + u ^{2} )} d u

= \int \frac{1}{6 ( 1 + u ^{2} )} d u

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= \frac{1}{6} \cdot \int \frac{1}{1 + u ^{2}} d u

Use the common integral:

\int \frac{1}{1 + u ^{2}} d u = arctan (u)

= \frac{1}{6} arctan (u)

Substitute back

u = x^{6}

= \frac{1}{6} arctan (x^{6})

Add a constant to the solution

= \frac{1}{6} arctan (x^{6}) + C

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\int 6 t e^{t} d t

y^{^{''}} + 4 y^{^{'}} + 40 y = 30 cos (8 t)

\int_{- 3}^{- 3} x^{2} d x

\int \frac{6 x ^{5}}{( x ^{6} + 1 ) ^{2}} d x

What is the integral of (x^5)/(1+x^{12)} ?
The integral of (x^5)/(1+x^{12)} is 1/6 arctan(x^6)+C