What is the sum from n=1 to infinity of 2+n/(3n+2) ?

The sum from n=1 to infinity of 2+n/(3n+2) is diverges

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sum from n=1 to infinity of 2+n/(3n+2)

n = 1 \sum \infty 2 + \frac{n}{3 n + 2}

diverges

Solution steps

n = 1 \sum \infty 2 + \frac{n}{3 n + 2}

Apply Series Divergence Test:

diverges

= diverges

\frac{s ^{2}}{( s + 5 ) ( s ^{2} + 2 ^{2} )}

\int \frac{( ln ( x ) ) ^{3}}{x} d x

\int sin (2 x - \frac{π}{4}) d x

x \to 1 lim (1)

y^{^{'}} = \frac{x ^{2} + 1}{3 y ^{2}}

What is the sum from n=1 to infinity of 2+n/(3n+2) ?
The sum from n=1 to infinity of 2+n/(3n+2) is diverges