What is the limit as x approaches 16 of (x^2)/2-8/x ?

The limit as x approaches 16 of (x^2)/2-8/x is 255/2

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limit as x approaches 16 of (x^2)/2-8/x

x \to 16 lim (\frac{x ^{2}}{2} - \frac{8}{x})

\frac{255}{2}

Decimal

127.5

Solution steps

x \to 16 lim (\frac{x ^{2}}{2} - \frac{8}{x})

Plug in the value

x = 16

= \frac{1 6 ^{2}}{2} - \frac{8}{16}

Simplify

\frac{1 6 ^{2}}{2} - \frac{8}{16} : \frac{255}{2}

= \frac{255}{2}

\frac{d}{d x} ((3 x + 2)^{5})

f (x) = 8 π x^{2}

\frac{\partial ^{2}}{\partial y ^{2}} (\frac{x y}{x - y})

x \to 4 lim (5)

\frac{d}{d x} (9 cos (3 x))

What is the limit as x approaches 16 of (x^2)/2-8/x ?
The limit as x approaches 16 of (x^2)/2-8/x is 255/2