What is the sum from n=0 to infinity of (-1)^{2n+1} ?

The sum from n=0 to infinity of (-1)^{2n+1} is diverges

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sum from n=0 to infinity of (-1)^{2n+1}

n = 0 \sum \infty (- 1)^{2 n + 1}

diverges

Solution steps

n = 0 \sum \infty (- 1)^{2 n + 1}

Apply Series Divergence Test

= diverges

\int sin^{2} (θ) cos^{2} (θ) d θ

\int \frac{1}{1 + 6 x} d x

\frac{d}{d x} ((x^{2} + 2)^{2} (x^{4} + 4)^{4})

5 x y \frac{d y}{d x} = 3

y^{^{'''}} - 6 y^{^{''}} = 6 - cos (x)

What is the sum from n=0 to infinity of (-1)^{2n+1} ?
The sum from n=0 to infinity of (-1)^{2n+1} is diverges