What is the derivative of-5x(2x-3^4) ?

The derivative of-5x(2x-3^4) is -5((2x-3)^4+8x(2x-3)^3)

What is the first derivative of-5x(2x-3^4) ?

The first derivative of-5x(2x-3^4) is -5((2x-3)^4+8x(2x-3)^3)

Popular >

\frac{d}{d x} (- 5 x (2 x - 3)^{4})

- 5 ((2 x - 3)^{4} + 8 x (2 x - 3)^{3})

Solution steps

\frac{d}{d x} (- 5 x (2 x - 3)^{4})

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= - 5 \frac{d}{d x} (x (2 x - 3)^{4})

Apply the Product Rule:

(f \cdot g)^{'} = f^{'} \cdot g + f \cdot g^{'}

f = x, g = (2 x - 3)^{4}

= - 5 (\frac{d x}{d x} (2 x - 3)^{4} + \frac{d}{d x} ((2 x - 3)^{4}) x)

\frac{d x}{d x} = 1

\frac{d}{d x} ((2 x - 3)^{4}) = 8 (2 x - 3)^{3}

= - 5 (1 \cdot (2 x - 3)^{4} + 8 (2 x - 3)^{3} x)

Simplify

= - 5 ((2 x - 3)^{4} + 8 x (2 x - 3)^{3})

\frac{\partial}{\partial v} (u (v, w) + v \cdot e^{w})

\int sin (2 x) e^{x} d x

p (x) = x^{4} - 3 x^{3} + 10 x^{2} - 6 x - 20

\int \frac{1}{( 3 - x ) ^{2}} d x

f (x) = 9 e^{x} + x, at x = 0

What is the derivative of-5x(2x-3^4) ?
The derivative of-5x(2x-3^4) is -5((2x-3)^4+8x(2x-3)^3)
What is the first derivative of-5x(2x-3^4) ?
The first derivative of-5x(2x-3^4) is -5((2x-3)^4+8x(2x-3)^3)