What is the integral of e^x(cos(x)+sin(x)) ?

The integral of e^x(cos(x)+sin(x)) is e^xsin(x)+C

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integral of e^x(cos(x)+sin(x))

\int e^{x} (cos (x) + sin (x)) d x

e^{x} sin (x) + C

Solution steps

\int e^{x} (cos (x) + sin (x)) d x

Expand

e^{x} (cos (x) + sin (x)) : e^{x} cos (x) + e^{x} sin (x)

= \int e^{x} cos (x) + e^{x} sin (x) d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int e^{x} cos (x) d x + \int e^{x} sin (x) d x

\int e^{x} cos (x) d x = \frac{e ^{x} sin ( x )}{2} + \frac{e ^{x} cos ( x )}{2}

\int e^{x} sin (x) d x = - \frac{e ^{x} cos ( x )}{2} + \frac{e ^{x} sin ( x )}{2}

= \frac{e ^{x} sin ( x )}{2} + \frac{e ^{x} cos ( x )}{2} - \frac{e ^{x} cos ( x )}{2} + \frac{e ^{x} sin ( x )}{2}

Simplify

\frac{e ^{x} sin ( x )}{2} + \frac{e ^{x} cos ( x )}{2} - \frac{e ^{x} cos ( x )}{2} + \frac{e ^{x} sin ( x )}{2} : e^{x} sin (x)

= e^{x} sin (x)

Add a constant to the solution

= e^{x} sin (x) + C

k = 2 \sum \infty \frac{3}{9 ^{k - 1}}

\frac{d y}{d x} = \frac{y}{x ^{2}}

\frac{d}{d x} (\frac{1}{1 - e ^{- x}})

\int e cos (x) d x

\frac{d}{d y} (\frac{a x + b y}{c x + d y})

What is the integral of e^x(cos(x)+sin(x)) ?
The integral of e^x(cos(x)+sin(x)) is e^xsin(x)+C