What is the derivative of f(x)=tan^5(x) ?

The derivative of f(x)=tan^5(x) is 5tan^4(x)sec^2(x)

What is the first derivative of f(x)=tan^5(x) ?

The first derivative of f(x)=tan^5(x) is 5tan^4(x)sec^2(x)

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derivative of

f (x) = tan^{5} (x)

5 tan^{4} (x) sec^{2} (x)

Solution steps

\frac{d}{d x} (tan^{5} (x))

Apply the chain rule:

5 (tan (x))^{4} \frac{d}{d x} (tan (x))

= 5 (tan (x))^{4} \frac{d}{d x} (tan (x))

\frac{d}{d x} (tan (x)) = sec^{2} (x)

= 5 (tan (x))^{4} sec^{2} (x)

Simplify

= 5 tan^{4} (x) sec^{2} (x)

\int \frac{( x ^{2} - 2 x + 1 )}{x ^{2} + x} d x

\frac{d}{d x} ((e^{- x} - e^{2}) (e^{x} + e^{- 5}))

\frac{\partial}{\partial x} (y - \frac{8}{x ^{2}})

\int sin^{5} (2 t) d t

\frac{\partial}{\partial x} (3 sin (x cos (y)))

What is the derivative of f(x)=tan^5(x) ?
The derivative of f(x)=tan^5(x) is 5tan^4(x)sec^2(x)
What is the first derivative of f(x)=tan^5(x) ?
The first derivative of f(x)=tan^5(x) is 5tan^4(x)sec^2(x)