What is the integral from 3 to 6 of (x^2) ?

The integral from 3 to 6 of (x^2) is 63

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integral from 3 to 6 of (x^2)

\int_{3}^{6} (x^{2}) d x

63

Solution steps

\int_{3}^{6} x^{2} d x

Apply the Power Rule

: [\frac{x ^{3}}{3}]_{3}^{6}

= [\frac{x ^{3}}{3}]_{3}^{6}

Compute the boundaries:

63

= 63

\int_{- 4}^{- 6} (- 2)^{- 3} d x

\int_{0}^{π} sin (2 x) d x

\int \frac{1}{( x ^{2} + 7 )} d x

y = 1 - 4 x, at x = - 1

x \to 9 - lim (\frac{x}{x - 9})

What is the integral from 3 to 6 of (x^2) ?
The integral from 3 to 6 of (x^2) is 63