What is the derivative of 3x^2+2x+5 ?

The derivative of 3x^2+2x+5 is 6x+2

What is the first derivative of 3x^2+2x+5 ?

The first derivative of 3x^2+2x+5 is 6x+2

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\frac{d}{d x} (3 x^{2} + 2 x + 5)

6 x + 2

Solution steps

\frac{d}{d x} (3 x^{2} + 2 x + 5)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (3 x^{2}) + \frac{d}{d x} (2 x) + \frac{d}{d x} (5)

\frac{d}{d x} (3 x^{2}) = 6 x

\frac{d}{d x} (2 x) = 2

\frac{d}{d x} (5) = 0

= 6 x + 2 + 0

Simplify

= 6 x + 2

x \to 0 lim ((7 x)^{3 x})

\int - cos (x) + sin (x) + 3 d x

\int \frac{cos ( x )}{sin ^{6} ( x )} d x

\frac{d y}{d x} = \frac{x}{18 y}

(2 x + t) \frac{d x}{d t} + (x - 2 t) = 0

What is the derivative of 3x^2+2x+5 ?
The derivative of 3x^2+2x+5 is 6x+2
What is the first derivative of 3x^2+2x+5 ?
The first derivative of 3x^2+2x+5 is 6x+2