What is the derivative of sec(xanx) ?

The derivative of sec(xanx) is an(xsec(x)tan(x)+sec(x))

What is the first derivative of sec(xanx) ?

The first derivative of sec(xanx) is an(xsec(x)tan(x)+sec(x))

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\frac{d}{d x} (sec (x) an x)

an (x sec (x) tan (x) + sec (x))

Solution steps

\frac{d}{d x} (sec (x) an x)

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= an \frac{d}{d x} (sec (x) x)

Apply the Product Rule:

(f \cdot g)^{'} = f^{'} \cdot g + f \cdot g^{'}

f = sec (x), g = x

= an (\frac{d}{d x} (sec (x)) x + \frac{d x}{d x} sec (x))

\frac{d}{d x} (sec (x)) = sec (x) tan (x)

\frac{d x}{d x} = 1

= an (sec (x) tan (x) x + 1 \cdot sec (x))

Simplify

= an (x sec (x) tan (x) + sec (x))

\frac{d}{d x} ((x^{2} + 1)^{\frac{3}{2}})

\frac{\partial}{\partial y} (x^{2} + sin (x y))

\int_{0}^{1} cos (x) d x

4 y^{^{''}} - y^{^{'}} + 2 y = 0, y (0) = 2, y^{^{'}} (0) = 0

x \to 3 lim (\frac{3 - x}{∣ 3 - x ∣})

What is the derivative of sec(xanx) ?
The derivative of sec(xanx) is an(xsec(x)tan(x)+sec(x))
What is the first derivative of sec(xanx) ?
The first derivative of sec(xanx) is an(xsec(x)tan(x)+sec(x))