What is the derivative of 2(x^3-x^4) ?

The derivative of 2(x^3-x^4) is 8(x^3-x)^3(3x^2-1)

What is the first derivative of 2(x^3-x^4) ?

The first derivative of 2(x^3-x^4) is 8(x^3-x)^3(3x^2-1)

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\frac{d}{d x} (2 (x^{3} - x)^{4})

8 (x^{3} - x)^{3} (3 x^{2} - 1)

Solution steps

\frac{d}{d x} (2 (x^{3} - x)^{4})

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 2 \frac{d}{d x} ((x^{3} - x)^{4})

Apply the chain rule:

4 (x^{3} - x)^{3} \frac{d}{d x} (x^{3} - x)

= 4 (x^{3} - x)^{3} \frac{d}{d x} (x^{3} - x)

\frac{d}{d x} (x^{3} - x) = 3 x^{2} - 1

= 2 \cdot 4 (x^{3} - x)^{3} (3 x^{2} - 1)

Simplify

= 8 (x^{3} - x)^{3} (3 x^{2} - 1)

\frac{d}{d x} (x^{2} - x y + y^{2})

\int_{0}^{1} \frac{63}{4 y - 1} d y

e^{x} (3 x^{2} - 6 x + 6)

x \to 0 - lim (7 - 2 x)

\int 3 x^{3} - 5 x^{2} + 3 x + 4 d x

What is the derivative of 2(x^3-x^4) ?
The derivative of 2(x^3-x^4) is 8(x^3-x)^3(3x^2-1)
What is the first derivative of 2(x^3-x^4) ?
The first derivative of 2(x^3-x^4) is 8(x^3-x)^3(3x^2-1)